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Comments:
<0> it's lunch time
<0> w00t
<1> [1] would be otherstuff
<2> by the way, bealtine
<3> well oncey ou apply [] you're within Type's operator=
<2> in that BaseArray, you can p*** Size to the vector constructor in the init list, instead of calling resize()
<1> thats a typo
<3> bealtine who are you talkign to, me or rd
<1> i just want to push_back /***ign
<3> your operator is for Array = stuff; not Array[1] = stuff;
<1> ah ha
<3> oncey ou apply []
<3> you are within Type's operator=
<3> what I think you want is the += operator
<4> even if you array[1]++ ?
<4> that's still operator=?
<3> then you can do Array += stuff; Array += OtherStuff;
<2> weird
<3> NineVolt in this example. Don't be annoying
<1> not intereste in Array =
<1> just the elements
<4> i tuned in late, wasn't trying to troll :P
<3> oh heh ok
<4> heh
<3> bealtine yea I ***ume you're not interested in that :P are you trying to use Array[1] and Array[2] etc
<2> bealtine why is a vector unsuitable?
<3> without worrying about whether or not that item exists yet?
<3> instead of calling Array.push_back(stuff); Array.pushback(otherstuff): ?
<3> wow, typos are fun
<2> int a[4]; a[1] = 3; a[2] = 7; vector<int> a(4); a[1] = 3; a[2] = 7;
<3> rdragon I think he wants that exact example, but without doing a(4); and instead just using the default c-tor
<1> yep
<3> so if that array item doesn't exist, it generates it?
<1> yes
<3> bealtine if that's the case, you must call resize within your [] operator and then you do'nt need the = operator
<3> though I do'nt recommend that method
<1> sort of
<1> Array[1] = stuuf does a Array.push_back
<3> bealtine what does Array[1] = otherstuff; do ?
<1> (stuff)
<3> push back ANOTHER element? even though you just used the same index?
<1> same
<2> this is oddly strange, bealtine ;)
<1> irrelevant :)
<3> this is really really strange hehe
<2> you always want [] to push_back ?
<2> no matter the index?
<3> sounds that way
<1> just dont want to run through acres of code changing Array[X] = stuff
<1> to Array.push_back(stuff)
<2> you don't have to
<2> ohh
<2> well, you shouldn't have to
<2> just change the array declaration
<2> from int a[4]; to vector<int> a(4);
<3> bealtine: Type& operator[](const int& i) { if(i >= size()) resize(i + 1); return at(i); }
<3> beal: pseudo code
<3> but if you do that you do'nt NEED to push back... when you access [] it will grow the vector to be a size capable of storing your new length
<3> I think you are overloading at the wrong spot
<1> possibly
<1> probably :)
<3> heh
<2> bealtine - why not what I said?
<3> if you use a method like I just posted, you will not need to overload any operator except []. However, it's kind of silly still
<3> everytime you access an element it wil lresize, so it's wasteful
<3> [11:39] <2> just change the array declaration <-- better solution
<1> the code builds arrays out of chunks of data
<2> so, it still must allocate the space ahead of time
<1> yes
<2> right
<2> ?
<2> ok
<2> so give the vector an initial size
<2> bam
<2> and all should be fine... ?
<1> but i need to know the pos of the current push_back at any time
<2> i guess we should look at the code you have existing
<1> not the size
<2> because this doesn't quite make sense ;)
<1> it was based around boost::array
<2> lets see how it's 'building'
<2> well boost::array has an initial size, too
<1> exactly which is where it fell down
<2> im not sure why you know the size, but still want to push_back
<1> i could tell how many elems where in there
<1> could/couldnt
<2> oh well shower/work time... good luck
<1> same with vector
<1> resize()/.size() pair only give you whatever size() was given
<1> if you follow
<2> i'd like to see this code that 'builds' the array
<2> to figure out what you're trying to plug this into
<1> ok
<1> some stuff on noidea
<2> ok so uh
<2> i dont see the problem
<2> unless you don't know the final size
<1> exactly
<2> you keep that 'running index' external
<2> ...exactly what?
<1> i dont know the size because variable length data gets appended to the arrasy
<2> oh, well there ya go
<5> hey guys
<5> what's up?
<2> bealtine if the statements look pretty similar, maybe a regex can help you change the code to push_back
<2> but that's the way I would go, instead of inventing some weird sorta-container
<2> gotta run though, good luck
<1> ciao
<5> I'm somewhat new to regexp, and I need to do a grep/substitution using a PCRE module. Can I do string substitution and grep matching at the same time?
<5> That is, I'm trying to do "this is foobar" -> "this is bad" using something like ".*/foobar/bad/"
<4> s/foobar/bad/
<4> CL : that's just retarded.
<4> but as though being retarded wasn't bad enough, that wasn't even english.
<6> =))
<6> you are a boot ....:D
<4> a constant velocity joint boot at that.
<0> good god bealtine sux0rs
<7> hi all
<7> I have an error in my code that says the functions in my header are being included in my project twice by two different dialog cl***es
<8> /work
<3> lies
<7> lies!!!
<7> hi vaw
<7> hi all
<7> I need to make it so that my header file doesn't get included in my project more than once
<7> I think it has to do with the fact that I do #include at several different levels in my project
<1> lookup header guards
<7> ok
<7> I used #if !defined Functions_h
<7> then #define Functions_h
<7> I will try #ifndef when I get home but that should have worked
<9> you can also use #pragma once
<10> http://www.theagitator.com/archives/026579.php#026579
<3> lol
<3> nice article NI
<0> well, found a bug in SOS
<0> !clrstack appears to have an infinite loop bug in it's stalk walk
<11> hello
<11> can someone help me abaut: want to know how can i delete something from my all comp one program, datebase
<7> yeah I didn't use pragma on mine, thanks I'll try it
<0> keeps walking the same frame over and over
<3> IkBe I have no idea waht you just said. try that one again
<4> anyone here have any experience with bittorrent?
<11> ?
<11> ok
<11> [m]aniac: i mean , how can i delete something (program/file) from my all comp , i don't want to be noone of parts
<12> hola
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