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Comments:
<0> follow the link
<0> <0> http://putfile.com/pic.php?pic=4/10501205513.jpg&s=x402
<0> diagram includes the circimcircle of ABC, and AD is the circumdiameter
<0> it's extremely crude, my apologies in advance
<1> I see what you mean
<1> That hypotenuse goes through the center of the circle?
<0> yes
<1> Well
<1> Doesn't complementary mean that they add up to 90 degrees?
<0> yes
<1> C alone already exceeds 90 degrees
<0> excust me
<0> supp
<0> didn't know i typed complimentary
<0> supplementary
<1> aso
<1> Hmm
<0> i'm using this diagram as part of my proof for the law of sines
<0> maybe that'll help you see what i'm aiming at
<0> if C and D are supplimentary, then that diagram proves that law of sines = 2R, where R is the radius of the circumcircle
<0> supplementary
<0> late :/
<1> :/
<0> lol
<0> thanks for even looking at it and trying to make -some- sense from it
<1> Is C at the center of the AB arc?
<0> no
<0> it's not isosceles
<1> Then I don't see how it could work
<1> Because if C were close to the ends of the arc, its angle would be radically different from in the middle
<1> But D wouldn't change
<1> So how can one angle change and another not change and they remain supplementary
<0> well yes it would, because the circumcircle would change
<0> the circle is formed according to the intersection of the perpendicular bisectors of ABC
<0> if the triangle changes, the circle changes, and thus D changes
<1> In a circumcircle, the center goes through the center of the triangle
<1> Not a hypotenuse
<0> if the oblique triangle is acute
<1> Oh, sorry
<1> Yeah
<1> This is way beyond my geometry, sorry
<0> er
<1> The dudes in #math might have some advice
<0> not even if acute, i'm thinking of the interior circle formed by the intersection of the angle bisectors, dunno wuts it called
<0> we tried :/
<0> thanks a bunch man
<0> Debug/tic_tac_toe.exe : fatal error LNK1120: 1 unresolved externals
<0> this error means i've got a bad function somewhere, no?
<2> you've declared something somewhere but not defined it
<0> ok
<0> thanks
<1> Failed to link something or you misspelled the function name or something.
<2> or defined it in a different namespace, or typo, or smomething
<2> word.
<2> moo
<1> Okay, jose
<1> Your answer did not satisfy me
<0> :/
<1> If C moves half the arc from C to A
<1> So that C is now at the midpoint of that former arc
<1> The circumcircle or whatever remains the same
<1> And the D angle remains the same
<1> And the C angle very likely changes
<1> Right?
<0> how would the circle remain the same if the triangle changes?
<0> circumcircles are unique circles
<0> because of how they're formed
<0> i see what you're saying, but the circle would change if the triangle changed
<1> Well, so long as C remains on the circumference of the old circumcircle, the new one will still be the same
<1> Right?
<2> er
<1> The circumcircle is the circle that p***es through all the vertices
<1> I thought
<2> are you talking about that trig problem that guy posted?
<0> well the radius touches the vertices
<0> geometry
<1> http://putfile.com/pic.php?pic=4/10501205513.jpg&s=x402
<2> this is high school trigonometry
<1> You ought to take this **** to #teenchat and blow their minds
<0> and i meant supplementary, not and C + D = 90
<0> there's no trig involved
<1> I know, but it still works with 180
<1> Stay with me here
<2> what? why not
<1> Why would the circumcircle change if C was right next to A on the current circumcircle's circumference?
<0> what are you using Cowmoo?
<1> mooometry
<0> because it's formed by the intersection of the perpendicular bisectors of ABC, so if C changes, the line segments change, thus the intersection and circumcircle change
<2> jose2: I don'ty remember the rules..but just find the size of D and C no
<1> This is jose's problem, Rag:
<1> http://putfile.com/pic.php?pic=4/10501205513.jpg&s=x402
<2> you know D because right triangle
<0> the only trig i'll be using is the sin of D, which is just sin(D) = c / 2R
<0> first though
<0> i want to prove that C + D = 180
<2> ?
<2> complimentary angles = they add up to 90
<0> lol
<0> read above
<2> where :-\
<0> <0> and i meant supplementary, not and C + D = 90
<2> oh
<0> my warning:d
<2> yea had me wondering
<0> lol
<1> Complementary
<2> right
<2> anwyay, still
<2> high school trig, use the various rules
<1> The circumcircle is a triangle's circumscribed circle, i.e., the unique circle that p***es through each of the triangles three vertices. The center of the circumcircle is called the circumcenter, and the circle's radius is called the circumradius. A triangle's three perpendicular bisectors , , and meet (Casey 1888, p. 9) at (Durell 1928). The Steiner point and Tarry point lie on the circumcircle.
<0> basically, you can do the same on paper. construct a triangle, let C be obtuse, form the circumcircle with the perp. bisectors, draw a segment from A that p***es through the circumcircle the the opposite side (let this be D)
<1> The unique circle the p***es through each of the triangle's three vertices
<0> yes
<1> You don't HAVE a circumcircle of ABC
<0> ?
<2> jose2: are you in high cshool
<1> Oh, you do
<0> lol
<0> lord
<0> no, why?
<0> i'm in a college cl*** just proving the law of sines for obtuse triangles
<2> oh
<0> precal
<2> is this an intro to maths cl***
<2> right
<2> so use your laws foo
<0> ...
<2> what
<0> i'm proving the laws
<0> how can i use the laws to prove them?
<2> what?
<1> Okay
<2> I thought you're applying them
<0> lol no
<0> <0> i'm in a college cl*** just proving the law of sines for obtuse triangles
<1> If you move point C, the circumcircle remains the same, so long as C is on the current circumference
<2> don't you want C+D = 180
<1> I don't understand how that's not true
<2> that sounds like application to me
<3> Two angles cannot be complementary angles if one angle is above 90 degrees.
<0> lol
<2> Ragtime^: right, was a typo, guy meant supplementary
<0> i should really upload an updated image huh
<2> this is stupid
<1> Don't worry about
<0> yeah
<2> I hate all you precalc monkeys
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