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Comments:
<0> sigh
<1> I watched green acres when I was a kid, dopey
<0> sure sure
<1> bleh
<0> looks like vista beta 2 borked over rdp, well done
<2> windows really ****
<2> 9GB
<2> is that the required disk space right?
<2> for windows vista?
<2> or 15GB
<3> who cares
<2> if not bcoz of programming
<2> i should stick to my Mac OS X Tiger
<3> use real english, I'm tired of this z ****
<3> do whatever you want
<2> ok
<0> now to see if they've fixed the ea downloader so that it doesn't depend directly on IE6 for some godforesaken reason
<4> is there a "list view" mode for windows explorer in vista?
<0> what do you mean
<4> like files are organized top to bottom and left to right
<4> and only scroll horizontally
<4> unlike detailed view that scrolles vertically
<0> i don't see one
<4> thats enough to make me want to uninstall this piece of ****
<4> god damn micro****
<0> okie dokie
<4> whats "sync" for?
<0> likely the next version of activesync, for partnering with mobile devices, cell phones, pdas, etc
<0> good, ea did fix the ea downloader
<0> so that it works on systems without ie6
<4> electronic arts?
<0> yes
<4> is it just me or did everyone else have to reinstall office?
<4> those that upgraded and did not clean install
<0> who knows
<0> i'd never upgrade, especially on a beta os
<3> peterhu do you use codeplex ?
<0> haven't yet
<0> i registered but that's it
<3> I just registered, but it won't let me connect to their team server
<5> hello
<5> i am interest of cee plus plus
<6> cee? Heh.
<7> c33
<8> you see
<9> if you instantiate a variable inside a loop, does it create a memory leak or does the scope of the variable end with each iteration?
<10> the scope ends
<10> better said when the scope ends the variable is discarded
<9> after each iteration, or after the entire loop exits?
<9> you're saying after each iteration right? so while(...) { int i = something; } is valid
<7> That i is unique
<7> As far as I know, it would very likely utilize the same memory space for all the i's in the loop
<7> But it would refresh that memory at each iteration, meaning that they're genuinely different variables.
<7> The scope is cleared at the end of each iteration, let's say.
<8> aldr0n : however, if your variable is of a custom cl***, and has constructor and destructor - it's a very good idea to declare it outside the loop, unless you need it to be constructed and destructed every time
<9> I'm just saying I had previously thought it created a memory leak to instantiate a variable inside a loop, until it occured to me just now that the scope would end
<7> No, won't cause any problem at all.
<7> It's not even a particular performance hit.
<9> I understand now.
<7> Try it in a loop of 4,000,000.
<7> Now, dynamic memory is a whole different ball game.
<8> JBlitzen : if the ctor is heavy - it is a performance hit
<7> Obviously when you new something inside a loop, you'd better be on the ball.
<7> exception, he's talking about ints, I ***ume he understands the difference between utilizing simple data types and complex data types
<9> well I need the value to stay the same, so I'm going to use the { } to make a temporary scope to intialize the var, then use it inside a loop
<9> yeah i'm not newing anything there
<9> well actually I am but I delete it too
<7> If you want the value to say the same, declare the variable outside the loop, or declare it as static.
<7> There's a relatively simple way to see how this works in practice
<8> creating a special scope is pointless - you can declare a variable at any point of the scope
<7> for (jlaskdfjasd)
<7> {
<7> Wait :/
<7> int *ptr;
<7> for (jalksdfjasdf)
<8> int X; for (...) {use X;};
<7> {
<9> i'm going to use { int var = something; while(var != something else) { var = somefunc(); } }
<7> Here's an idea, why don't you all type over me
<9> sry
<7> int *ptr;
<7> for (asdf)
<7> {
<7> Damn, missed yet another step
<7> int *ptr, x = 5;
<7> ptr = &x;
<7> for (asdf)
<7> {
<7> cout << *ptr;
<7> cout << (double)ptr; // or whatever
<7> int y = 23;
<7> ptr = &y;
<7> }
<8> casting a pointer to a double.... you'll get some interesting results
<7> That will lead to some very interesting results, I think.
<8> aldr0n : why do you use the external scope ?
<7> See my point in that code, aldr0n?
<9> i think so
<7> It should result in gibberish at the second iteration
<7> Although the memory address might actually stay the same
<7> It would be even more interesting if you try to write to *ptr
<7> Should work fine the first iteration, then give a runtime error the second.
<7> Because the space it's pointing to at the second iteration is essentially deallocated at the end of the iteration
<9> yeah
<7> Now why don't you tell us what you're trying to do
<9> i think I've got it
<9> I was just wondering that about scope
<7> k
<7> As a general rule, anything inside {} is in a unique scope
<7> That's not always the case, and it's not exhaustive, but it's a good guideline
<7> Actually, it might always be the case, and it might be exhaustive, but I'm too tired to think about it right now.
<7> Interesting!
<7> Check this out
<7> int *ptr, x = 0;
<7> ptr = &x;
<7> for (int m = 0; m < 4; m++)
<7> {
<7> std::cout << *ptr << std::endl;
<7> *ptr = 5;
<7> int y = m;
<7> ptr = &y;
<7> }
<7> Output is:
<7> 0
<7> 1
<7> 2
<7> Press any key to continue . . .
<11> [enter]
<7> :/
<11> is that unexpected somehow?
<11> makes sense to me.
<7> I'm surprised the *ptr = 5 was permitted
<7> That indicates that each iteration is not in fact a unique scope
<11> howso?
<11> ptr is declared outside the loop...
<12> Heh
<9> ptr previously pointed to x at that time, which is still in scope
<7> Yeah, and that's right
<7> BUT
<7> [05:47] <7> ptr = &y;
<7> y is a local variable within the iteration scope
<11> right, that was just initialized to another local value.
<11> and then you point to it.
<12> You're just lucky it doesn't crash
<11> just because y goes out of scope doesn't mean ptr stops pointing to it.
<7> Ignoring NineVolt, who seems to have short circuited, that's my point, ashe.
<12> Not sure what's interesting about it, you're only 4 bytes "out of bound" on the stack
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