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Comments:
<0> hi?
<0> hi
<1> Hi Dayus.
<0> hi
<0> :)
<0> im seeking help
<1> Okay.
<1> Help in what?
<0> you know nasm?
<1> I don't use nasm.
<0> hmmm
<1> Is it a problem with NASM or ASM in general?
<0> well i guess both
<0> im not very good in ASM
<1> Maybe you can tell me about the problem.
<0> and i have a work to do ...
<0> im a lil confuse
<1> You mean school ***ignment? :]
<1> Nevermind, explain your problem.
<0> the notes given by the teacher are not clear at all
<1> Paste me the note.
<0> its like 84 pages in pdf :P
<1> hmm....what's the point of the whole note?
<0> it talk a lot about memory
<1> Okay.
<1> And?
<0> but very little about the operation
<1> It ***umes you have the basics to work by the instruction given by the manual.
<1> Anyway, maybe you can get into the point.
<0> like if id like to know about MUL
<0> its doesntn explain it at all
<0> it show not clear example of its use...
<1> That's when your INTEL manuals comes in handy.
<0> really?
<0> :P
<1> Yes.
<0> i should check it out
<0> but anyway
<0> i want to check the marks of student
<0> to see how many there is that are over 90
<0> so the mark scale is from 0 to 100
<0> and they say its stored in a single bytes unsigned integer
<0> and right there im confuse
<0> 1 byte is 4 bits
<2> no, 1 byte is usually 8 bits
<0> so 4 binary number
<0> 8 bits
<0> oups
<0> ok
<0> so 8 binary
<0> making 2 hexa
<0> 00h
<0> right?
<2> yar
<1> So?
<0> so 0 to 100 would be
<0> 00h to ...
<0> hmmm
<2> 64h
<0> oh thanks
<2> max value of a byte is FFh
<2> which is 255
<0> so
<0> all result above 5Ah
<0> is to be counted
<2> ok
<1> Dayus: What's the real problem?
<0> i dont know how to do it...
<1> You can't do the ***ignment or there is something wrong in the code?
<1> Which part exactly?
<0> how do you compare
<1> cmp
<1> cmp eax, 4
<1> for example
<0> so i do cmp ebx, eax
<1> Yes.
<0> eax being 5Ah
<0> ?
<1> I dont really know whats the value inside EAX
<0> but thats not telling me its over 90% it tell me its the same...
<1> It depends to you
<2> say your byte is in al.... cmp al, 5Ah | jg OVER_90 | jmp FAIL
<0> in ebx i put the socre of one student
<2> jg == jump if greater
<1> jge
<0> aawww
<0> yes
<0> so i do the cmp
<2> ok yep... jge is the correct one
<0> and after
<0> i do the jg
<1> jge
<0> make sens
<1> Yes.
<2> no jge... jump if greater or equal
<0> ok
<1> Yes, he have a range to check Inode.
<1> HE won't be taking only 1 point.
<0> if not i dont increment if it is i do increment my register...
<2> i meant....
<2> no to... <0> i do the jg
<1> Okay.
<1> Sorry, misread it.
<2> heh bad grammar sorry
<0> well thanks guy
<1> Np, bad sight ^_^
<0> i should be able to do this easy one :P
<1> I guess so.
<0> but some more difficult ahead :S
<1> Dauys: How are you getting the scores of the students?
<0> i should have kept my old notes about ASM
<1> Through a file or a hardcoded array?
<0> they dont really specify
<1> I see.
<0> i just have to write part of the code
<1> You will write a function then.
<0> they say it start a some address
<1> Ahh, okay.
<1> Then it wil be p***ed to your function
<1> Just ***ume the data is p***ed to you in EAX or something
<1> and start working from there.
<0> so i just do a add [ebx], something
<0> to move in the memory
<1> Why?
<1> Why would you add?
<0> cause the score a 1 byte
<0> so i move ebx one byte everytime
<0> to see the next score
<0> no?
<2> you don't use add for that
<1> inc
<0> inc is one byte?
<0> wait
<1> I think 1/2
<1> That's not HALF, btw.
<1> Inode: I think he doesn't know what he's talking about.
<1> Am going to sleep.
<1> Goodnight!
<0> so you want me to do inc [ebx]
<2> inc is increment by 1, it'll work for 8 (al), 16 (ax) and 32 (eax) bit regs
<0> ok
<2> you would do... inc ebx
<0> wont it increment the value in ebx?
<2> because i guess ebx would hold a pointer (address of the scores) to the scores
<0> yes
<0> ok
<2> yar
<0> i get it
<0> ok ill try to write it
<2> so to get the next byte, you'll add 1 to the pointer
<0> make sense
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