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Comments:
<0> you can use two substitutions, but that might not quite be what you want
<1> Do you think this can solve my problem?
<0> hmm
<0> the bracket nesting makes things interesting
<2> hello all
<1> goldfish, bearPerson: Thanks for thinking about my problem.
<1> wish you a good night.
<3> u 2
<0> only thing I could think about is s/\((.*\)patt\(.*)\)/new/
<0> er
<0> only thing I could think about is s/\((.*\)patt\(.*)\)/\1new\2/
<1> But the problem is that pattern patt could occur multiple times and so you need the 'g' option but this option would include the \1\2 which occurs only once.
<0> *nod*
<0> kay, mean trick time
<1> Ok, i have to finish to reach my bus. If someone get something like a brainstorm he can send me the idea as email.
<1> My address is Vasudva.Martin@gmx.de
<0> s/^[^(]*(/&\n/; s/)[^)]*$/\n&/; tloop; :loop; s/\(\n.*\)patt/\1new/; tloop
<1> I take a look to your suggestion tomorrow. I saved it in an file.
<0> kay
<1> bye
<0> see you
<4> anyway to substitute a multiline string using sed ? Something like sed {/OLD_STRING/"$new_multiline_string"/g}
<5> grepper: You forgot the s command.
<4> heh, true
<5> grepper: s/pattern/line1\
<5> line2\
<4> anyway, it doesn't work
<5> line3/
<4> yeah \n works
<4> but $new_multiline_string is a var
<5> \n only works on GNU sed
<5> Well, and others probably.
<4> so \n is not helpful
<5> Inserting shell variables with arbitrary contents is never a good idea.
<4> I did an awk solution that works ok, but was still curious if it could be done with sed
<5> s,[%`"\],\\&,g
<5> s,\n,\\&,g
<4> hm, sorry I don't understand that one, where is the var ?
<5> safe_var=$(echo "$unsafe_var" |sed -e 's,[$`"\],\\&,g' -e 's,\n,\\&,g')
<5> <input sed -e 's/pattern/'"$safe_var"'/g' >output
<5> safe_var=$(echo "$unsafe_var" |sed -e 's,[$`"\],\\&,g' -e 's,\n,\\&,g' -e 's,/,\\&,g') ## oops, forgot the delimiter.
<5> er, sorry, that won't work :
<5> mksafe() { echo "$1" |sed -e 's,[$`"\/],\\&,g' -e '$!s,$,\\,'; }
<5> <input sed -e 's/pattern/'"$(mksafe "$unsafe_variable")"'/g' >output
<5> http://www.rafb.net./paste/results/evZrnc11.html
<5> I forgot I wrote that a while back.
<4> ok, suppose the input is already in that format ? line1\ line2\ etc ?
<5> Well, then you don't need to put \\ at the end of each line.
<4> sure, but still need to substitute the multiline var for something
<5> Hmm?
<4> as I said originally: sed {s/OLD_STRING/"$new_multiline_string"/g}
<4> using line1\ it would output it all on one line, no ?
<4> it has to stay multiline
<5> printf 'foofoo\n' | sed -e 's/foo/1\
<5> 2\
<5> 3/g'
<5> It works for me.
<5> Unless I'm misunderstanding what you want to do.
<4> foo="a
<5> printf 'foofoo\n' |sed -e "$(printf 's/foo/1\\\n2\\\n3/g')"
<4> multiline string"
<4> it works with \n, but not with a literal newline
<5> As you have it, it will not work.
<4> hm
<5> http://www.rafb.net./paste/results/eu7MyE88.html I fixed clean_for_replacement()
<5> sed 's/OLD_STRING/'"$(clean_for_replacement "$new_multiline_string" /)"'/g'
<4> playing with it, thanks
<4> hm, that puts new_multiline_string all on one line
<4> I get unterminated `s' command
<4> if I don't escape EOL in the input
<4> and if I do escape it, it gets put all on one line
<4> phebehouse.dyndns.org/tovid/multiline_sub.sh
<4> ah, it was the newline after __BUTTONS
<4> working now
<4> thanks prec
<6> can I tell sed to be --line-buffered ?
<7> woah!
<7> first action int he whole day :)
<6> it's -u if someone cared
<6> s
<7> h :)
<7> ah
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