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Comments:
<0> hi all
<1> hi
<2> I want to replace a @ with a \@ how can I do that. I am trying escapes but I am doing something wrong
<2> I was doing sed s/\@/\\@/ test > test2 but that was not working
<1> @ is not special
<1> sed 's/@/\\&/g'
<2> I am replacing a string with a variable but the variable looks like this root\@localhost.com. So the sed command is sed s/youremail/$var/ file1 > file2 but when it gets into file2 is looks like roo@localhost.com/ I need the \ to be there though
<2> the replace needs to be root\@localhost.com
<2> nm got it
<3> fyi
<3> http://www.scschools.org/jobs/jobs.htm
<4> Hi, is it possible to address lines _not_ matching a regex?
<4> oh... I see it in the man page.
<4> (just missed it)
<5> hello
<6> hi
<5> how do I put a regular expresion indicating end of line
<5> I mean:
<7> $ is the eol in sed
<5> echo "hello.sig@mail.com.sig" | sed 's/.sig//g'
<5> I would like: hello.sig@mail.com
<7> ok
<8> \.sig$
<5> :-D
<5> thanks
<5> I put it at the beginning
<5> thanks a lot
<5> another question :-D
<5> how could I execute more than one `command`
<5> for example
<5> echo `for n in `find /var/spool/dspam/data/ -type f -name "44b268d9237726491211187.sig"`; do basename `dirname $n`| sed 's/\.sig$//g'; done`
<5> the are two `cmd`
<5> one inside the other
<7> echo "hello.sig@mail.com.sig" | sed 's/.sig$//'
<5> yes I know
<5> but the echo is not the command
<7> echo "hello.sig@mail.com.sig" | sed 's/.sig$//;s/hello/HELLO/'
<6> helllen, is you question more to do with the embedded command syntax than the sed syntax?
<6> not that i know the answer either way. ;p
<5> I solved it
<5> /usr/bin/dspam --user $(for n in `find /var/spool/dspam/data/ -type f -name "44b27d8c278731622883445.sig"`; do basename `dirname $n`| sed 's/.sig$//g'; done) --source=error --cl***=spam --signature=44b27d8c278731622883445
<5> it was actually a bash command
<5> bash problem
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