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<0> DanF_DrC: why did you leave? <0> your university? <1> irbdavid: i think polylactic acid (PLA) is also really interesting :) <1> but cant find anything like that inside my house <2> hehe wow. some story <3> yo <2> is there a theoretical limit against a compressor heat transfer being great enough to drive itself? <4> you mean a like a carnot engine? <2> not familiar with that <4> i think wiki's article is pretty good <4> haven't checked it in a while though <2> does it answer the question? <4> i don't really understand the question <2> seems the carnot is just the one half of the question <2> you can transfer more heat energy using a compressor than it takes to power it <2> question is, is it enough to power the process
<4> i'd ***ume not, b/c that would be a perpetual motion machine <2> yes but ***umption is the mother of all ****ups <4> so if i understand your system well enough <4> you have a compressor (let's say a piston), and we are providing work to it <4> is there enough thermal energy to in effect continue the compression? <4> is that what you are asking? <2> like an earth heat system, is the heat transfered enough to power the transfer <2> for instance in my country such earth heat commercial systems exist for heating houses. drawing from a radiator in the ground where the ground is always 6c yeat heats the house to 20+ while being far more efficient than using the compression energy directly for heating <2> yet* <2> essentially free energy. you follow? <2> off to bed <4> sounds like a refrigerator <4> sorry was grabbingf a sandwich <4> but a carnot engine is the ideal <2> np. same principle just in reverse. but there is more to it. teh self powering part <4> you can do what you are talking aboutbut it's efficiency will be less than the carnot's <2> what I am talking about is perpetual motion <4> i know <4> which is why i don't believe it <4> like the topic says take it up w/ boltzmann <2> hehe but he's dead <4> i'm just starting statistical mechanics <4> so you'll have to wait for me to prove it <2> it's not about statistics. it's about understanding <4> what year university are you? <2> and if you don't dare to think for yourself I wont wait for you to tell me that it works :) <2> I'm out. degree in comp sci. not physics <4> ah <4> what's the interest in physics then? <5> there is interest in physics ? <5> we should have it taken out and shot <2> alunduil, UFOs <4> lmao <2> laugh it up fuzzball <4> i'm trying to connect UFO's and perpetual motion machines is all <5> well have you ever known stories about ufos to go away ? <5> that's kinda perpetual :P <5> i can make a perpetual motion machine easily :P <2> trying to attack the problem of where current science has overlooked something vital <2> http://www.df-cad.dk/web/ufo/Clinton95.avi <5> sorry i do not have the internet here DanF_DrC <2> I ***ure you it's very real. whether you can handle it or not <4> i consider UFO's to be moot, sorry <5> so i cannot view your video <2> then stay ignorant <5> pmsl <4> i shall, but i will learn physics <6> oh look, a new war <7> huh <7> what is it good for? <6> lol <8> hello... my beer, which comes in a regular 12 oz beer bottle, is 35 degrees fahrenheit coming out of the fridge, it's 80 degrees in the room, and the beer is best served at 50-54 degrees... how long should i leave it out before pouring? <6> you want the diff eq or just a number <8> hondje: i'd like to know the answer and how to figure it out <6> look up newtons law of cooling <6> it's a fairly simple ODE <8> ok
<6> but, to solve it you need to check the temp at both t=0 and t=n, to figure out what t is when the beer is 50F <8> does the formula take into account the shape of the thing? <8> oh you're saying i need two data points to figure out the rate <6> yeah <8> right? <6> yep <8> k <8> i have to get a thermometer then <6> The shape is generally irrelevant unless you're obsessive about it <8> what about if i blow a fan at it? <8> how much diff does that make <6> probably get dust in your beer <6> You can take either a simple ODE, or you can make it a thermo cl*** final problem :-) <9> come on people! <9> Temperature change is exponential <8> hondje: no dust, the caps still on <8> JohnFlux: how would you solve it then? <9> well you do indeed need a second data point :) <6> So, what you do is this <6> First, you open a beer and drink it to determine the temp <9> noah: you can imagine that the rate it cools at will be different depending on how fast it cools <6> then drink the second one, and note the time elapsed <9> hondje: ;-) <6> now take two shots of tequila - I prefer Patron, but you can go your own route here - and you won't care <9> noah: uh <9> noah: i mean that the rate it cools at will depend on how thick the gl*** is etc <6> Same thing, really <9> why 2 shots? <9> noah: what you can do is find a physics student <9> and say "here's a free bottle of beer. in return tell me how long it takes to reach 50-54 degrees" <6> JohnFlux: Because you can't just have one shot of patron :) <6> oh yeah, that's a good idea <6> we'll do all sorts of stupid **** for beer <6> or poon <8> heh <8> i doubt i can offer you poon <8> this is beer you give away by the sip tho <6> Why, is it special beer? <8> yeah it's a fancy belgian style <6> oh yeah? What's it called? <6> New Belgian Brewery makes a nice one called Abbey, I highly recommend it to anyone west of the mississippi <8> hondje: it's called hennepin <8> brewed in cooperstown, ny <10> humm <11> yo <10> anybody know about hovercraft here? <10> I want to know how changing the area of the base is gonna affect how much weight it can lift. <10> Would I be right in saying that to calculate velocity pressure in N/m squared you use the formula VP=0.6xV^2? In my case, VP = 0.6x77.7^2 = 3622.37 N/m^2 Is this the right formula to be using for what I'm after? <12> hey...anyone alive? <13> mefistofeles: no i died about 2 days ago <12> ahh damn! <12> couldn get here 2 days ago <12> that sux <12> JabberWalkie: do u know something about qed? <13> mefistofeles: absoltely <13> nothing <12> heh <12> well Im just starting <12> with some feynman's lectures <13> mefistofeles: ahh fun... <12> JabberWalkie: do u study physics or something related? <14> man...it's late <13> genoobie: go to bed! <14> okay oaky...nite! <15> morning Jreggelt! <16> Hi <17> Hi. <2> hi <16> let's talk about neutron stars and their magnetic fields now! <16> So, the neutron star rotates real fast, got a magnetic field the poles of which are off by some angle to the rotational axis <16> there's the 'light radius', which is the radius at which an object that moves with the same angular velocity as the star would reach the speed of light <16> I wonder, what happens to the magnetic field lines if they reach out to the light radius? <2> there is no such thing as magnetic field lines
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