| |
| |
| |
|
Page: 1 2 3 4 5 6 7 8 9 10
Comments:
<0> yeah i thought that too <0> and put a WHERE id<30 for example <1> Silent******in: You may need to: SELECT * FROM (SELECT .. ORDER BY ts DESC LIMIT 40) ORDER BY RAND(); <1> Silent******in: If you have numeric id and can make sure it has all values 1..80 you can simply generate random number(s) from 1 to 40 and your task becomes very simple <0> i thought that too , i'm doin it in php ... <1> Silent******in: In brief the better you define the problem the better solution you will find :) <0> but i don't want to write too much :P <0> i am doing a tester .. to test myself german past tenses <0> cause i have test tommorow :( <2> does anyone have any info on connecting to mysql via a .net application with c#? <0> square never done that myself so i done something a bit diferent <2> what did you do different? <0> just outputed the mysql table with a php script , and import it from c# language <2> um <0> imported the output <2> i want to insert data from my c# application
<0> oh <0> depends what data <2> nothing fancy <0> you can also do a php script to add data that were received using GET method <0> in that case you could use #c to do something like open adress "http://blabal/script.php&data=blabla <2> yeh <0> now i go to study <2> cya <0> cya <3> how can i make a join between Dog(dogid, name, ownerid) Owner(ownerid,name) where ownerid of Dog references ownerid of Owner <4> !m bladhasd JOIN <5> bladhasd: (JOIN Syntax) : http://dev.mysql.com/doc/mysql/en/JOIN.html <4> SELECT d.dogid DogID ,d.name DogName ,d.ownerid OwnerID ,o.name OwnerName FROM Dog INNER JOIN Owner USING (ownerid) WHERE (whatever) <6> ok dba's/developers <6> I'm lost <6> I have a user that cannot connect to a database <6> I cannot understand why <7> the error is a good start <6> access denied <6> standard user can't connect <7> full error <4> the *complete* error is a good start <6> ok <6> ERROR 1045 (28000): Access denied for user 'demo1'@'localhost' (using p***word: YES) <4> wrong p***word <7> or no user for that ;) <4> wrong user/p***word then <6> I would normally agree with you <6> however I've just changed it <6> and flushed the privs <6> to make sure <4> how did you change it? <6> on the last occasion I've used the mysql-administrator tool <6> however before I just uset the set p***word <6> option <7> what did you change? <8> what's the canonical way to handle a link from table A where for each A it can link to *either* table B *or* table C? <8> or nothing, of course. <6> Leithal in what way <7> muhoo: two foreign keys <8> Leithal: that's what i have. but it doesn't capture the either/or nature of it. <8> i've been hacking around it with application code <6> I just did <8> i.e. table A has foreign keys for B *and* C <6> set p***word for 'demo1'@'%' = P***WORD('$P***'); <9> add a new explicit entry for 'demo1'@localhost <6> well, I can do that. But surly if % is not even connecting, thats a pretty serious config problem <9> I believe % does not cover localhost. if you try using the actual IP of the system with --host, it may work right now. <6> just adding localhost now <9> I have always seen and made entries for localhost and "%.domain.com" <6> testing.... <10> Isn't LIKE supposed to be case insensitive? <6> well I'll be buggered with a fish fork <6> infi thank you very much <7> muhoo: which way are the relationships then? <6> adding a localhost account was spot on <9> ikonia ;) <7> sorry was afk <7> Setien: no <7> us BINARY LIKE <6> all the databases I've created and I've never known that
<6> big thanks <9> cheers <10> Leithal, but binary like IS case sensitive, right? <7> right, any "BINARY" comparison is <7> WHERE BINARY foo LIKE .. <10> Leithal, but I wrote "case INsensitive" <7> oh <7> well it is by default then <10> Leithal, so rephrased: LIKE is supposed to be NOT case sensitive, right? <7> unless you are using some binary collation <7> right <10> Leithal, do you know if a binary collation can be implied if you are doing something like this: <10> WHERE IF(data_type='String',value_string,value_number) LIKE '%foo%' <10> ? <7> that should be case insensitive <7> _unless you are using a binary collation_ <10> Leithal, now my if statement is somewhat more complicated and includes CASE and IF nested with both INT and VARCHAR columns, and the results coming out are case sensistive <10> Leithal, I am not using a binary collation unless it's something I am doing inadverdently <10> like it's doing it when I use CASE WHEN <10> or something <7> if you have an example that would be good <7> it may be that you are trying to cast between data types, and that may be effecting it I guess <7> but an example would help <10> Leithal, hold on <10> http://pastebin.com/551189 <10> focus on the last bit of the WHERE <7> more info <7> what values do you have, what are search strings returning? <7> what strings are you using that cause "wrong results"? <7> if you compare a string to a number, then the string will be cast to an int <7> and that will, if a pure string, be 0 generally <10> I have a string called "Seating/Chairs" which isn't matching against the search "cha" <10> but it matches "Cha" <10> I'll try a cast <10> hold on <11> sup channel <10> Leithal, this'll take a bit - I am hving problems getting it to accept the cast syntax <12> I am completely new to mysql. I would like to use it to create a calendar application on my website. Is there a easy to understand tutorial for mysql where I can learn the basics of operating it? I am particularly interested in tuts geared towards Linux users <9> !tell evolocus about tutorial <5> Alrighty. <12> infi, whats the diff between sql and mysql <11> anything look wrong with query? $updatesqli = mysql_query("UPDATE `records` SET `type` = 'I' WHERE `record_id` = '$record_id") or die('Query failed: ' . mysql_error()); <9> SQL is an acronym meaning Structured Query Language, a (generally) standard language for communicating with an RDBMS. MySQL is an RDBMS (relational database management system) <11> II keep getting this: You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near ''' at line 1 <13> well well what do we have here <9> mike_: '$record_id" <11> yeah i noticed still does it : syntax to use near '' at line 1 <10> gah <13> gahhh <11> haha <12> are mysql users same as system users? <10> Can't I do something like this CAST(IF(a>b,mynumber,mystring) AS VARCHAR) to make sure that evne if a is bigger and the INT column is used, I will still get the column casted to a varchar <11> as in linux system users? <9> evolocus, no <12> mike_, yes <12> oh <9> there is a separate access system for connecting to the database <11> infi said the answer lol <12> is the user creating part included in the tutorial? <9> probably, I've never read it ;) <9> why don't you look and see? <12> ok <12> I am right now <11> evolocus, I just use phpmyadmin <10> Leithal: It works - I just needed to cast it to a CHAR <12> what is phpmyadmin <7> ;) <11> http://www.phpmyadmin.net <11> infi, so any other ideas? <9> eh? <11> I changed it to this and still getting the same error: $updatesqli = mysql_query("UPDATE records SET type = 'I' WHERE record_id = $record_id") or die('Query failed: ' . mysql_error()); <9> ... <9> are you sure $record_id isn't empty? <1> mike_: Dump the query text as you send it and only then you will be able to see what's going on
Return to
#mysql or Go to some related
logs:
waveforce gentoo #linuxhelp named.conf keeps reverting gmailfs Unable to find account configuration xorg.conf gamepad #php cannot open/read repomd.xml file for repository fedora 5 #php livna_release #bash
|
|