| |
| |
| |
|
Page: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
Comments:
<0> Vamp1, yes, so after the first year, there's 7200 people. then you take 1% of that, and subtract
<0> or you could just do what the formula says
<1> Are there ever times when you HAVE to use say, u-substitution as opposed to integration by parts?
<0> > 8000*(.99^5)
<2> The operator `.' [infixr 9] of a section
<2> must have lower precede...
<0> > 8000*(0.99^5)
<2> 7607.920399199999
<0> > 8000*(0.99^15)
<2> 6880.466837130307
<3> 7650
<3> for 2000
<4> sorry just been a while since i did highschool maths just realised i forgot those terms
<0> no, these are the two answers
<1> I mean, integration by parts and u-substitution have pretty much the same problem domain, right?
<5> Squall`: no
<3> 6950
<3> for 2010?
<1> Don't they both deal with integrating the product of terms?
<5> Squall`: integration by parts is basically (f*g)'=f'g+fg', substitution is f(g(x))'=f'(g(x))g'
<0> Vamp1, I GAVE YOU THE ANSWERS
<0> and EXACTLY how to get them
<1> oh
<1> I see.
<0> geez
<1> so you just integrat ethe product and chain rules respectively?
<1> We haven't actually learned integration by parts. I was just peeking ahead.
<5> Squall`: you can sorta connect them if you consider the function m(a,b)=a*b, them by parts becomes m(f,g)'=f'*g+f*g' using partial derivatives
<5> Squall`: but yes
<3> wahh
<3> how come
<3> it dunt equal 7650?
<3> or not 6950
<0> look, it's just plugging into the formula
<5> chessguy: i got Vamp1 on iggy
<0> 8000*(.99^t), where t is the number of years since 1995
<3> iggy?
<1> Ignore.
<3> ahh
<3> ok
<6> heh... it's not linear, y'know :)
<3> it says
<0> TRWBW, congratulations. would you like a medal?
<3> p=8000(1-0.01)^t
<6> heh... my favorite type of these problems is the continuously increasing
<3> but ok
<0> Vamp1, yes, that's the same thing
<5> chessguy: no, just mentioned it to point out, that is a valid option
<0> TRWBW, i'm well aware of that
<3> ok thank you chess
<0> TRWBW, that didn't solve his problem though. a little patience, on the other hand, did
<5> chessguy: you are a saint among men
<1> -+
<0> i just try to contribute, because i know others have contributed to help me
<5> chessguy: next time some guy is being really dense, i'll direct him to you. you don't mind?
<0> i help because i admit to needing help sometimes. unlike those who think they know it alll
<0> s/ll/l/
<5> chessguy: no reason to make a mean of it. your tolerance in this case was higher than mine. if you got through to him, good job.
<3> chess
<3> maybe you can help me
<3> how do i graph the equation y=(1/3)^x
<6> Vamp1: that's simply 3^(-x), right?
<3> yep
<6> just choose a few points...
<3> 1/3=3 ?
<6> and connect the dots
<0> Vamp1, probably at your level the best way is to make a chart. pick a couple of x values, and find the ***ociated y values
<6> heh... it becomes 3^(-x) since it's the recipriocal
<6> heh... even at a high level... the chart seems to be the best way also, I think
<6> except that you calculate a few derivatives, etc.
<6> maybe critical points, max and mins, asymptotes
<0> or just pull out your TI
<0> :)
<3> how do i graph the equation y=(1/3)^x after a reflection in the y axis
<6> I don't trust my TI for graphing it - the graphs are quite poor IMO
<6> Vamp1: simply negate the numbers
<3> how do i negate it
<5> Vamp1: do you know what reflection means?
<6> 1 => -1, 3 => -3, -27 => 27
<3> yeh
<3> lieka mirror
<3> i used it in math
<5> sorry, may be a failing of me, i'm not proud of this, but i'm putting Vamp1 back on iggy
<3> like i care trw
<0> why do you feel you need to announce this to the channel, TRWBW ?
<0> we don't care
<3> chess so 1/3=3 so i just grap the 3^x o nthe graph at point 3
<3> then its reflection?>
<6> 1/3=3 - that's recripocal, not reflection
<6> 1/3 => -1/3, that's reflection
<5> chessguy: i tell people when i am ignoring them. it wasn't directed at you.
<0> 3^(-x) = (1/3)^x
<0> messages directed at individuals are what the /msg command is for
<3> wait
<3> chessgy in the beginnin it says to graph y=(1/3)^x
<3> 1/3 not 3/1
<7> Vamp1: 3^-1 = 1/3.
<3> 1/3^x
<3> is the equation
<7> Vamp1: So (1/3)^x = (3^-1)^x = 3^-x
<0> Vamp1, that's the same thing as graphing 3^(-x)
<3> ok so
<3> 3^(-x) = (1/3)^x and how do you grapth that on a graph you go up 1 over 3 ?
<3> ?
<8> Vamp1: just find y-intersect and a couple more points
<3> wait dimitri how do i plot 3^(-x)
<9> can anyone help me prove that sum(i=1..n,1/i^2) <= 2-1/n using induction?
<8> y = 3^(-x)=1/3^x, what is y-intersect?
<5> Thad, are you sure?
<9> i think so...did i write it wrong?
<3> 1/3
<7> Vamp1: To find the y-intercept, you plug in x = 0.
<5> Thad, maybe 1/(i^2+i) or something like that would be better
<3> 3
<3> the y intercept is3
<10> graph y= -x - 7
<5> Thad. whoops, <= i thought you were writing =
<9> you're saying that it's not true?
<9> ahah yeah
<9> <=
<10> go down to -7, then put points left 1 up 1?
<3> im tryin 2 graph y=(1/3)^x
<5> Thad, use 1/i-1/(i+1)=((i+1)-i)/(i*(i+1))=1/(i^2+i)
<3> crisco me?
<7> Vamp1: Remember that anything to the 0th power is one- so use that information to find the y-intercept.
<10> Vamp1, i dont know if u can help me
<5> Thad: you can also use integral, do you know calculus?
<9> yeah but we don't want to go there
<3> rich its 1
<10> TRWBW, can u help me, plz, i only have 2 hours b4 ***ignment is due
<5> Thad: well that's two ways to prove it. the first thing i said and the second
<5> CriscoBoy: ?
<10> graph y= -x - 7
<10> go down to -7, then put points left 1 up 1?
<5> CriscoBoy: it's a line, do you believe that?
<7> CriscoBoy: Perhaps you could reword your question? I'm not sure exactly what you mean.
<11> crisco, down
<10> it says, graph the equastion by plotting points
<5> CriscoBoy: on a piece of graph paper, all you need is to find two solutions and then use a ruler to draw a line
<10> i have to solve it?
<3> rich?
<5> CriscoBoy: do you think you could graph y=-x
<10> ah i got ya
<10> put in values for x... right?
<5> CriscoBoy: that works just fine
<11> graphing annoy's me
<11> it takes too long to draw the lines
<9> kk TRWBW I'll play with the first thanks
<5> Thad: np.
<12> !8 Will my hyundai nickel and dime me to death?
<5> w00ts0n: hyundai is a fine value in a car.
Return to
#math
or
Go to some related
logs:
synaptic apache2-mpm-prefork
#math
install ubuntu ralink-driver
AZREUS 3,0
debian psmouse mousedev vmware
FFMPEG encoding not supported!
GUARDIANATOMOS
#math
#web
#linux
|
|