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Comments:
<0> one to many ]
<1> % Integrate[Sin^2[x],x]
<2> blocky: Integrate[Sin^2[x], x]
<1> lol
<1> hmm
<3> % Integrate[Sin[x]^2,x]
<1> % Integrate[Sin[x]^2,x]
<2> woggle: x/2 - Sin[2*x]/4
<2> blocky: x/2 - Sin[2*x]/4
<1> ah ty
<1> woggle how would i integrate that manually
<4> blocky: just use the linearization formula for sin,wich turns it into a constant plus some cosinus and then integrate
<4> (sin^2 => constant + some cos )
<1> sorry, im not following
<1> i dont know what the linearization formula is
<4> blocky: just square the half-angle identity http://en.wikipedia.org/wiki/Trigonometry#Half-angle_identities , the first one
<1> ah ok
<1> cool thanks
<0> does mbot support rounding?
<5> Can anyone help me with where to start on this one? : http://www.infoleak.org/content/formulaImage.png
<6> % Round(3.33)
<2> Crashed: 3.33*Round
<5> It is a definite integral
<6> % Round[3.33]
<2> Crashed: 3
<0> % Simplify[590 - (290 + sin[PI/4]*(Ceiling[D/S] * 8))];
<2> Chase-san: Null
<0> % Simplify[590 - (290 + sin[PI/4]*((D/S) * 8))];
<2> Chase-san: Null
<0> % Simplify[y=590 - (290 + sin[PI/4]*((D/S) * 8))];
<2> Chase-san: Null
<6> % sin[PI/4]
<2> Crashed: sin[PI/4]
<6> % Sin[PI/4]
<2> Crashed: Sin[PI/4]
<0> oh
<6> % PI
<2> Crashed: PI
<0> % pi
<2> Chase-san: pi
<0> ah ha
<0> % Simplify[y=590 - (290 + sin[pi/4]*((D/S) * 8))];
<2> Chase-san: Null
<0> or not
<6> % help
<2> Crashed: "See http://documents.wolfram.com/v5/ for detailed Mathematica help."
<0> % Solve[y=590 - (290 + sin[pi/4]*((D/S) * 8)),y];
<2> Chase-san:
<2> pi
<2> 8 D sin[--]
<2> 4
<2> General::ivar: 300 - ----------- is not a valid variable.
<2> [8 @more lines]
<0> meh
<7> Chase-san - /msg mbot @math ...
<0> what now?
<8> <8> do you guys agree with this proof? a, b \in G . (ab)^2 = a^2 * b^2 => G is abelian
<8> <8> suppose there exists a pair ab != ba. Then, (ab)^2 = abab. However, since (ab)^2 = abab = aabb = a^2*b^2, there is a
<8> contradiction if ab != ba by definition. Therefore, (ab)^2 = a^2 * b^2 => G is abelian
<0> % Simplify[y=590 - (290 + Sin[pi/4]*((D/S) * 8))];
<2> Chase-san: Null
<0> meh, nvm i'll try to figure this mess out
<4> clarity_: you are wrong
<5> Can anyone help me with where to start on this one? : http://www.infoleak.org/content/formulaImage.png -- it is a definite integral
<8> spx2 : what's wrong with it/
<9> is it true that if you add scalar multiplication of vectors to an affine space it becomes an euclidean space?
<4> clarity_: tell me your exact problem
<8> for every a, b in G (ab)^2 = a^2 * b^2 implies G is abelian
<8> prove.
<10> clarity_: It's a little unclear (and also you don't need to do it by contradiction), but it works
<9> spx2, btw I read parts of the book you gave me, now I have a better notion of what an affine space is and its application in geometry
<7> clarity_ - suppose (ab)(ab) = a^2 b^2 for all a,b in G. left-multiplying by a^(-1) and right-multiplying by b^(-1) yields bab = a b^2 and then ba = ab.
<9> although it's far from clear :)
<4> vns_: it will be clear if you solve problems
<4> azadder: look at this http://www.mathlinks.ro/Forum/viewtopic.php?t=118309 , before trying to solve what you have there http://www.mathlinks.ro/Forum/viewtopic.php?t=118309
<2> Title: MathLinks Math Forums :: View topic - impossible integrals
<5> spx2, thank you
<8> Catfive: thanks
<9> spx2, sure, problem is I have to study for exams and most of this stuff is not explained
<4> vns_: i suggest for exams you go about it this way : 1)first take all definitions and learn them 2)read once all theorems(not the proofs),just like a lecture,if you dont understand,just continue 3)read the theorems again reading also the proof and note the ones you didnt understand,also make sketches where appropriate for your better understanding 4) take a look again at all the theory with...
<4> ...proofs 5)solve problems with the theorems youve learnt
<9> yeah, that's some good advice, trying to understand everything proves impossible
<9> because most of the time I get into too advanced material I can't comprehend
<4> vns_: that is very often my problem also,so i would suggest the first step is to know definitions
<4> vns_: its actually a very big step
<4> vns_: if you know the definitions you're 1/4 through ...
<4> vns_: 1/4 is theorems and proofs and the rest is solving
<4> vns_: its very important to look at solved problems also
<4> vns_: and its very important to solve as much problems as you can
<5> spx2, read the articles, understand now that this is somewhat of a "trick" question, but, the homework says that I should round the answer to the nearest hundreth decimal place... I do apologize for asking so much of you, but would you guide me further?
<5> (the homework is online and isn't taking the answer of just writing the integral)
<8> in cyclic notation, for the group of one-to-one mappings that are onto with composition as the product. Does (1 3)(1 2 3) = (1 2)
<8> ?
<4> azadder: its simple if it asks for approximations,just use taylor expansion for e^sqrt{t} and you just have to integrate a polynomial (dont take all the taylor series,just the first ,say 30 terms or so,check and see how much you need to do a accurate integration
<5> I wish I knew more about what you were saying
<5> thank you, again
<4> what did you not understand ?
<4> azadder: http://en.wikipedia.org/wiki/Taylor_series#List_of_Taylor_series_of_some_common_functions <-- this is for a formula to calculate an approximation to e^x with a polynomial
<2> http://tinyurl.com/3yqp9g
<4> azadder: take the first 30 terms of that sum,and integrate them
<4> azadder: thats all you have to do
<5> spx2, thank you very much
<4> your welcome
<11> Aha.
<11> malik: you still there?
<12> ihope: yah...
<4> azadder: id say you'd also have to use a high precission library with functions... like miracl
<5> it's not that important, I promise
<11> malik: the third paragraph of "Proof of the paradox" is indeed incorrect.
<12> ihope: yes... i'm no native speaker... but i thought so too
<11> It should read "For any particular person who is not drinking, it still can't be wrong . . ."
<12> yes
<12> ihope: perhaps i will write something on the discussion page, or will you? :)
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