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Comments:
<0> sorry
<0> i dont know either really
<1> hi
<2> vns_, what's the question?
<1> could you give me a hint how i can integrate (1/xln(x))dx ?
<3> delta, a_n and b_n have 2 and 3 subsequential limits respectively, I want to prove that a_n + b_n diverges
<0> litb: integration by parts?
<1> i tried u-substitution by u=1/ln(x) but that did not work
<2> vns_, such as in a_n = (-1)^n?
<4> litb: u=lnx
<4> FTW
<5> FTW OMG BBQ LOL LMAO
<3> delta, yes
<6> vns_: show that if a subsequence a_{i_1}, a_{i_2}, ... converges to P, then the sequence b_{i_1}, b_{i_2} must be a convergent subsequence to L - P, where L is the limit of a_n + b_n (***uming that limit exists)
<3> rashakil, well, I see this is implied by the fact that if a_n -> a, and b_n -> b then a_n + b_n -> a + b, but then how would the e/3 help in this case?
<1> yeah, substitution by u=lnx works. but why u=1/lnx doesn't work?
<6> vns_: maybe e/2 would work; certainly e/100...
<1> i differentiated 1/lnx by using the quotient-rule (h'g - hg')/h^2 by having h=1 and g=lnx . can't i do that?
<6> vns_: actually forget the epsilon.
<6> vns_: just use that to show that a_n has a third subsequence
<6> with a third limit
<1> doesn't that work because 1 is constant?
<7> hey, does bot support matlab?
<3> well, a_i -> P, b_i -> L - P, a_k -> Q, b_k -> L - Q then b_l should converge to L
<3> I don't see anything wrong with that
<2> It's like combinatory, in fact :)
<3> am I going in the right direction?
<2> vns_, enumerate the different cases, you won't have the choice.
<8> hi, what does this mean, in matlab: x = -pi:pi/10:pi; ?
<8> actually i think i know ;)
<7> !matlab test
<3> delta, I'm not sure what you mean, but what if such points exists, wouldn't then a_n + b_n converge?
<7> !mbot test
<7> mbot test
<9> % Integrate[Log[x], x]
<10> excelblue: -x + x*Log[x]
<9> now that's a test :)
<2> vns_, don't want to conflict with rashakil :) but, if I were you I'd consider subsequences converging to l_1, then l_2, limit points of (a_n). Then, I'll insert l'_1, l'_2, l'_3, limit points of (b_n).
<3> insert? where?
<11> The probability of being dealt a full house in a hand of poker is ~ 0.0014. What is the probability that in 1000 hands of poker you will be dealt at least 2 full houses?
<2> vns_, as indicated above. There must exist subsequences of (a_n) converging to l_1. If (a_n+b_n) is supposed to converge to l then there is a subsequence of (b_n) converging to l - l_1. But that must be l'_1, l'2, or l'_3.
<11> Can't you say that is the same as 1 - { P(0 full houses) + P(1 full house)} ?
<8> quick q: in matlab, how do I graph simple functions? for example y = 1/x ?
<6> delta: you're not really conflicting with me; not with the latest version of me :)
<2> vns_, without loss of generality, you can ***ume it's l_'1. Now, do the same for l_2. Then start with (b_n) instead of (a_n).
<0> eduardo: x = [1:0.01:10]; y = 1./x; plot(x,y)
<2> rashakil, al right :)
<12> Hello folks. What does the symbol which is like an =, but with 3 bars instead of 2, usually mean?
<13> ahahaha
<12> It's from an electronics textbook where it says the voltage gain is given by: Av = Vo/Vi, except that the equal symbol actually has 3 bars.
<2> hedos, 'congruent' or 'isomorphic'.
<8> EvanR: oh, I was missing the dot after the 1. What does that do? does it for all the items on the list or something?
<14> it is an enochian sigil against fertility
<0> hedos: congruence or is definied as
<2> hedos, oh, identically then.
<0> eduardo: it does element-wise division
<12> identically? What does that mean?
<6> hedos: they're just saying that's the definition of Av.
<12> ok
<0> eduardo: like A*B is matrix multiplication and A.*B is element-wise multiplication
<2> They're funny.
<8> EvanR: would you agree that y1 = 1 ./ (0.4 .* x); is the same as y = 1/(0.4x) ? in matlab
<0> eduardo: yes
<8> thanks!~
<7> @plot 1/sqrt(1-x^2) @ xmin:0,xmax:1,ymin:0,xres:0.001
<10> Adg: http://nanographer.nanosouffle.net/?func=1/sqrt%281-x%5E2%29%0A&xmin=0&xmax=1&ymin=0&xres=0.001
<7> There server seem to be down..
<3> delta, well I think I got it, basically you're saying that if I take l'_3 there should be a subsequental limit l3 in a_n that is equal to l - l'_3, but there isn't
<15> hi
<2> Adg, works here.
<3> is it correct?
<2> vns_, well, not exactly, but that's a way to rephrase it, in a second step :)
<15> how can this be a valid set? {0^n 1^n | n = 0,1,2 ...} since 0 raised to anything is undefined?
<15> will undefined be a member of this set ?
<15> err 0 raised to 0 is undefined
<3> delta, where am I wrong?
<16> niles: It's probably a string
<17> How long does it take for an investment to double in value if it is invested at 5% per annum compunded monthly?
<16> "", "01", "0011", etc.
<15> thermoplyae: ahh yes i am reading up on grammers.
<15> so how did you derive that.
<15> where do the exponents come in.
<16> Well, I looked at it and I recognized that it was a cl***ic example of DFAs
<16> Ah
<17> anyone know how to do this problem?
<16> The exponents mean a repetition count
<16> So a^3 = "aaa"
<15> thermoplyae: thanx alot. this makes perfect sence now.
<15> thanx buddy
<16> If two things are juxtaposed or they have a composition symbol, that typically means concatenation
<16> np
<2> vns_, the first step would be l = l_1 + l'_1 = l_2 + l'_2.
<2> vns_, the second step would be l = l'_1 + l_1 = l'_2 + l_2 = l'_3 + ?
<3> delta, and the second step is what I said?
<3> aha.. well it's ok but it doesn't look very mathematical :)
<2> vns_, you're wrong. It is :)
<18> does anyone know a fast long number package for java or c#?
<19> udo, maybe use a non .net package called from c#?
<3> delta, I see, well thanks you, I understand the proof but can't really write it down
<3> but that would suffice for now
<2> vns_, not that difficult. Think in terms of subsequences, and eliminate cases.
<19> (there certainly is a jave package, prolly a free one, though i can't name 1 off hand)
<19> s/jave/java/
<20> Hey, I have a predicate logic question.. If Q(x, y) is "student x has been a contestant on quiz show y", where the domain of x consits of all students at my school and the domain for y consists of all quiz shows on TV. I need to express "There is a student at my school who has been a contestant on _Jeopardy_ and on _Wheel of Fortune_." Is it okay to express it like this: \exists x Q((y = Jeopardy AND y = Wheel of Fortune) --> x, y)?
<3> delta, when I take the subsequence of b_n which converges to l'_3 what do I say about the remaining subsequence of a_n (I've eliminated those which converge to l1 and l2)
<3> delta, that it doesn't have a limit?
<18> JKnecht: I would not want to use a non native package - I need to build up hash lists with about 2^20 entries - that would be to costly using interop or working across dll boundaries
<2> vns_, the corresponding subsequences of (a_n) is converging, so its limit must be l_1 or l_2. No choice.
<2> vns_, *err, subsequence.
<3> aha, I see
<3> thanks, it makes sense now
<19> udo: if you're doing lists of bignums that large, you've already got problems. First thing that would run relatively easily on DOS that comes to mind is the ocaml libs.
<21> Hello here's a simple math term question - what's the "name" of the mathematical symbol when referring to error correction
<21> e.g., in programming one does, if(fabs(someVar - 1.000f) < 0.5f)
<22> SANiK - 'distance'
<21> noo
<21> It has a wierd name like lambda or something
<23> epsilon?
<24> are you talking about delta?
<21> epsilon ... hmm I'm thinking that's it
<24> that typically represents a difference between 2 things
<16> epsilon is it
<24> epsilon is typically a distance
<2> pardon?
<21> lol delta
<21> delta go back to idling
<21> hmm, is there a site with these symbols
<21> and their name + common usage
<16> Not really
<16> But <float.h> is the file in which epsilon is declared in ANSI C
<24> google would probably know if there is one or not
<16> That's about all the information we've got for you
<23> std::numeric_limits<double>::epsilon() <-- the C++ way
<18> JKnecht: I just found the the java package java.math.BigInteger
<23> C and C++ have GMP, which is very nice
<25> hello everyone i'm confused on where they are getting these bounds, i'm converting into polar coordinates and i'm doing a double integral, the orignal problem is: doulbe int e^(-x^2-y^2) dA; D is bounded by x = sqrt(4-y^2); the answer is: int -PI/2 to PI/2 d(theta) * int 0 to 2 re^(-r^2) dr; well i think i figrued out how they got 0 to 2, becuase x = sqrt(4-y^2) == x^2 + y^2 = 2^2 so raidus = 2, but how did they get bounds -pi/2 and pi/
<2> what's GMP, me22?
<23> GNU Multi-Precision
<23> C++ wrapper has overloaded operators too, to not have to do the java .add() nastiness
<21> Been bored - having fun coding a "robo vision" type thing in C by loading a single Bitmap and then ripping it to shreads =O
<2> me22, sorry, I don't understand.
<26> how do i prove induction from well-orderding?
<27> A movie theater has been charging $7.50 per person and selling about 400 tickets on a typical weeknight. After surveying their customers, the theater estimates that for every 50 cents that they lower the price, the number of movie-goers will increase by 35 per night. What ist he demand function?
<27> Can someone help me with this?
<9> PuppiesOnAcid: well... let's take a look
<9> for $7.50, you sell 400 tickets...
<9> now, for $7.00, you sell 400+35(1)
<9> and so on
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