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<0> hi all! If I've groupping in regular expressionin gawk, how could I acces that groups value later, for example in print command?
<0> could anyone help me?
<0> also {} statement afrer grouping doesn't work in regular expressions =(
<0> for example /([[:digit:]]){5}/ doesn't matches 5 digits =(
<1> redbaron: see --re-interval
<1> about using the grouping matches, don't know (if it is possible, even)



<0> thx for re-interval advice
<0> but access to grouping matches is a great feature of regexp, very usefull to parse text, tables, etc =(
<1> redbaron: ah, see gensub for it
<1> gensub() function
<1> not sure if it is awk or Gawk-only
<0> oh grat thx!
<2> moo
<3> foo
<2> bar communication (tm xmb)
<2> gensub is gawk only
<4> trying to process a file with a format of " [0-9]+ [0-9]+ [a-z]+" e.g. " 22 10 somename" where the $3 has multiple entries, I am trying to sum up $1 and $2 per unique $3.
<3> Ober: post an example line of text you want to use awk on
<4> 1 22 proj.home
<4> I have used prev before for single line add ups
<4> just was not sure the proper way to sum by $3. if using an array would work for 2 values
<3> post the output you want awk to create from the line: 1 22 proj.home
<5> ober, awk '{ data[$3] += $1 + $2 } END { for (i in data) print i, data[i] }'
<4> gnubien: 2 44 proj.home
<4> sum($1) sum($2) $3
<4> having more than one value I was not sure how to do it with an ***ociative array
<3> Ober: ($1*2) ($2*2) $3
<5> ober, awk '{ data[$3] = 1 ; d[$3, 1] += $1; d[$3, 2] = $2 } END { for (i in data) print i, d[i,1], d[i,2] }'
<4> nice
<5> always



<4> yeah need to up my awk foo
<5> buh bye gnubien
<4> this is quick, and I tire of "do it in perl"
<4> thanks again, will take a while to grok this
<5> np
<5> its simple
<5> the =1 is optional
<4> yeah
<4> I was accessing the elements wrong as well
<5> gg
<4> cat foo|awk '($3 == "test") { value = $2 } END{ print "value is:" value }
<4> ok a line that has " 2007 22 test"
<4> add a question to the end of that last statement
<4> basically I ***umed that would work
<6> Ober: Oh, it's working.
<4> I guess it does work as a oneliner.
<6> Ober: It'll work better if you don't omit the 'if' statement before the first test.
<4> that's a consolidation from a script where \n is right before END
<4> ok
<4> oh well a oneliner works I guess
<4> thanks
<4> ($4 == "afs_cells") { afs_cells = $3;}
<4> END{ print "afscells:" afs_cells ;}
<4> ... found 54 'afs_cells' entries
<4> first two lines from foo.awk last line is the input


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