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Comments:
<0> I'm not certain what these yield statements mean.
<0> for instance: yield [i for i in range(len(int_ary)) if int_ary[i] == 1]
<1> yield statement makes a function a generator
<1> or actually a generator-maker, to be precise
<0> but what does the term in brackets mean with regard to yielding?
<2> the thing in brackets is a list comprehension
<0> If int_ary is a variable in the generator function
<2> it isn't necessarily ***ociated with yielding
<2> in fact, typically you'd use yielding instead of iterating like that
<0> So it says return the index whenever the value of the index is one, but that would seem to be multiple indices in the array?
<0> So you can yield multiple values?
<2> unfortunately this particular yield statement is mixing you up
<2> you can yield any object at all, even composite ones like lists
<2> the expression yielded here is a list comprehension, which is a way of iterating over a list, transforming it, possibly filtering it, and getting back another list
<2> so here a list is being yielded
<2> type this in your interactive interpreter:: [x**2 for x in range(10) if x % 1 == 0]
<2> that's a list comprehension
<0> According to the way the program I first implored about works, it appears that only one value is returned- by the yield.
<2> correct
<0> will do...
<2> only one value is being yielded -- but it's a list
<2> as I mentioned, using a list comprehension and then yielding the result is a bit unusual
<2> so you're seeing something inherently kind of weird
<0> What determines the value that is yielded out of the list?
<1> mmia: the list is yielded
<1> def foo ():
<1> yield [1,2,3,4,5]
<1> the list jus thappens to contain a few integers
<2> yes
<2> lists are objects just like anything else, they can be yielded
<2> for x in foo(); print x, type(x)
<2> that will print the LIST [1, 2, 3, 4, 5], not the ints 1, 2, etc.
<0> When I do print ilen(foo(i)) """ where foo is a generator yielding a list, I get one value, and I'm not sure what that is"""
<2> you lost me
<0> woops
<0> sorry, one moment.
<0> I think what the program is doing is trying to count the elements in the list that is yielded. Thank you for your help.
<2> it sounds like it
<2> but if it's only ever yielding one value, it might as well just return it (and not be a generator at all)
<1> mmia: look up for an example of using generators to represent e.g. the fibonacci series or some other infinite series
<1> the lazy-eval property gives some insight to the concept
<3> Hello everyone
<2> hello
<4> I've defined an object in the main file of this app, and I'm using a function which interfaces with that object from an imported file, when I compare globals() from the function and from the other file though, the object I defined is missing, any way to remedy this?
<2> globals are really module-specific
<2> you'll have to p*** the object in question in to the other module
<2> or, put the object in a third module which both the main and the other module import
<4> Bleh.
<4> The problem is that this function is supposed to be like a more complex getattr
<4> It's supposed to take the object and attribute as strings, and if the attribute is callable, it returns the result of the function, and if not it returns the attribute.
<2> then why is it in another module?
<4> The project is a text adventure dev. library, all the stuff that does the work is in one file, the game you create is in the main file, which imports the library.
<2> so why can't you p*** the object in?
<2> modules don't have intimate knowledge of the modules which imported them, that's the reverse of how module systems generally work
<4> Hmm.
<4> I just started with the idea of everything being strings, good point.
<2> a module provides functions/cl***es that are available to other modules (including the main module) which import them
<4> I'll try it without strings for the object name and see if I run into any complications, *slap self* Thanks.
<4> Actually, quick question, is there a way to call a function with arguments defined by a list?
<4> So in otherwords call("add",[3,5]) to replace add(3,5)?
<5> I think add(*[3, 5]) works..
<4> madewokhe, it does.
<6> hi. I'm totally new to python. Although I've ddone a lot of hacking with asp * vbscript. anyhow, I'm wondering what's the most user friendly web framework that I can sick my teeth in
<6> to develop some web app?
<6> sick/sink
<7> anyone awake?
<7> ready for some python a sunday morning
<2> y
<7> here comes a small apaste
<7> import Crypto.Util.RFC1751
<7> text = key_to_english(key)
<7> print text
<7> NameError: name 'key_to_english' is not defined
<2> is it defined in RFC1751?
<2> you meant from Crypto.Util.RFC1751 import key_to_english
<2> you meant:: from Crypto.Util.RFC1751 import key_to_english
<2> (for clarity)
<7> thanks! yes exactly
<2> if module M contains function f, then you can do:: import M; m.f()
<2> errr, import M, M.f()
<2> or from M import f; f()
<7> much obliged
<8> hi all , we will talking woth Paul Everitt after few minutes in #foss_sesions you are welcome
<9> hello
<10> has anybody tried using os.popen (any variant) to control a shell? e.g., os.popen4("bash") or something?
<11> is it possible to make python ignore the chmods of files in windows xp?
<11> and delete them even though they are +r ?
<1> how about chmodding the directory and the file writable?
<1> but on XP you should really use Windows' own permission controls, I guess they're available through the win32 extension
<11> the problem is that i dont use python myself and need to modify a script using shutil.rmtree that are unable to remove a file in the structure that is chmodded read-only
<11> yesterday i was told to use walk() but then ill have to modify the script to such extent that im not sure it will work correctly even though it appears so
<11> its a backup-script for subversion
<11> hot-backup.py
<11> the dream would be to use rmtree() and make it ignore the permissions :)
<11> but i suppose that is not possible looking at python reference libraries
<11> well, ill figure it out...thanks for your time
<11> i think i figured it out, im gonna chmod the file explicitly
<11> makes the script ugly though
<12> I am having trouble running mod_python in debian(sarge), can I pick someone's brain about it?
<13> what's the problem?
<12> i used this demo:
<12> http://www.modpython.org/live/current/doc-html/inst-testing.html
<12> but it only worked if i changed the import line to:
<12> import mod_python.apache as apache
<12> instead of the the import ised in the manual:
<12> from mod_python import apache
<12> when i try to use mod_python.publisher as the handler, i get various errors.
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