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<0> can anyone tell me whats wrong with this <1> what's the error <0> when i press submit it shows the else part <0> it dont send a mail <1> then you can be pretty sure that the IF isn't right <2> no way <0> what can i do <1> fix the IF part <0> how? im not good at scripting <3> how did you manage to write what code you have if you're no good at scripting? <0> i just figured it from the reference <0> have seen it in other form processors <3> www.php.net/tutorial.forms <0> ok thanks
<4> Ssup all <5> whats wrong with <?php include("folder/file.php"); ?> folder is in same directory and file.php is in the folder <6> echo getcwd(); <5> ? <6> <?php echo getcwd(); include("folder/file.php"); ?> <5> i simply want to include a file..which is in a folder of same directory <5> but simple include should work.. <5> isnt it? <6> Kingfisher, is that so hard to add that echo's ? <5> no its not but i just wanted to know why it doesnt work ? <6> your answer is inside that echo <5> okay thanks <7> you need "." to be in the list of include directories <7> or the absolute path <7> i forget if it is by default :/ <8> Hello, someone could tell me an another option that imagecreatefromgif because i have an gd version < 1.6 and need to open an gif file , resize and save id.. <4> imagemagick <8> DjKaye <8> i have no access at server <8> to install imagemagik <8> .. <4> uh <8> so isn`t another way to open an gif <8> ? <8> .. <4> Uhmm <4> iI might be wrong <4> but nope <9> morning fellas <10> howdy <9> what's up man? <2> sup <9> **** here. bout to go and find some damn breakfast. <9> you? <2> drinking my coffee <2> i think im going to the beach in a little bit <9> true that <9> where you stay at again? <2> in between houston and galveston <9> ah. the longhorn. <2> just texan <9> true <9> bbiaf. im freakin starving <4> ssup yo <11> I need to select this form list values if it exists in some table.. <7> indeed. <11> so I'm running another query inside the loop which is generating the list values <11> or filling up the list values <9> werd <9> sup pizza boy <11> the query is fine.. but it's not selecting anything <11> <option value="<? echo $row_getSoftwares['id']?>"<? if ($totalRows_ifexists > 0){ echo "selected=\"selected\"";} ?>><? echo $row_getSoftwares['Name']?></option>
<11> this is what I'm doing <7> hey ansimation ! <9> Timbaktu: try doing it inside of 1 set of php braces. <9> what's up man? <11> now it selects everything <9> Timbaktu: isn't that what you want it to do? <11> I want to select only if the value exists in this other table <11> so I'm running a second query to select where the id matches <11> or is there a simpler way? <7> ansimation: working on a release, taking calculus course, got a FreeScale dev/test kit from a friend i'm going to play with <7> you? <12> Timbaktu: a join <9> ****. about to write an article on digital copyrights for my website and then play with wigga some. maybe write a photoshop tv feed parser or something for him. <11> groogs: join? not sure about that.. first of all I need to populate the list with all the values from this table, and then I need to select if it exists in this other table <12> so you have one table that has a bunch of options, and you want it to be selected if it exists with some constraint in another table..? <11> yes <12> well, theres lots of ways.. one way: SELECT o.option_id, IF(ISNULL(s.option_id), 0, 1) as selected FROM options_table o LEFT JOIN selected_options s ON s.option_id = o.option_id <12> (maybe also WHERE s.user_id = 53 or something, if you only want certain data) <11> wow.. this is over my head <11> didn't understand the first query <9> then your best bet is to study the manual <12> IF(ISNULL(s.option_id), 0, 1) as selected <4> http://www.w3schools.com/sql/sql_join.asp <12> that creates a new field called "selected" .. if option_id (from the seleted_options table) is null, it will have a value of 0, otherwise, 1 <12> "FROM options_table o " is the same as "FROM options_table AS o" which makes an alias, so i can type "o.option_id" instead of "options_table.option_id" .. just laziness <12> for the LEFT JOIN part, go to that url that DjKaye posted <12> http://www.tizag.com/sqlTutorial/sqljoin.php <12> A Left join returns all rows of the left of the conditional even if there is no right column to match. <11> what is holding all the options? s table ? <12> selected_options (s) is the table that may or may not have an option_id <12> (eg, it determines if its selected or not) <11> okay.. let me see if I can do this <11> groogs: you're the man <11> the query looks good.. <11> now let me see if I can implement it right <11> there is only one other problem.. there is another field involved <11> in the s table I have this other field which is being p***ed in the url.. so I need to select only the ones in s table where both is true <11> but at the same time I need everything from o table <11> how can I throw a where clause here? <11> or maybe another left join! <11> a little help please <4> inner join <11> DjKaye: can I use inner join and left join in a single query? <11> how can I use an inner join here with an external variable? <11> you guys gave me a half solution! :( <2> Timbaktu: are you bitching about free help? <13> Please insert $100 for the next 5 minutes. <14> Timbaktu: you want to inner join with an external variable? that makes 0 sense. <12> Timbaktu: LEFT JOIN selected_options s ON (s.option_id = o.option_id AND s.othervalue = 5) <11> groogs: again you rock <11> thanks so much <10> um, what? <10> alright then <15> wtf does pamit mean? <15> I think that was Pakigrish. <14> it means goodbye <14> in indonesian <15> I see <15> Indoglish
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